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QJEEM20Phdcfb: JEE Main 2020 Physics - Class 11 JEEM20Phdcfb Solution: Consider two solid spheres of radii R 1 = 1m, R 2 = 2m and…

Consider two solid spheres of radii R1 = 1m, R2 = 2m and masses M1 and M2, respectively. The gravitational field due to sphere (1) and (2) are shown. The value of M1M2{{{M_1}} \over {{M_2}}} is : JEE Main 2020 (Online) 8th January Morning Slot Physics - Gravitation Question 145 English

Multiple Choice Options

  • A 23{2 \over 3}
  • B 16{1 \over 6}
  • C 12{1 \over 2}
  • D 13{1 \over 3}

Step-by-Step Verified Solution

Gravitational field on the surface of a solid sphere

E = GMR2{{GM} \over {{R^2}}}

By the graph

E1 = GM1R12{{G{M_1}} \over {R_1^2}}

and E2 = GM2R22{{G{M_2}} \over {R_2^2}}

∴\therefore E1E2=(R2R1)2(M1M2){{{E_1}} \over {{E_2}}} = {\left( {{{{R_2}} \over {{R_1}}}} \right)^2}\left( {{{{M_1}} \over {{M_2}}}} \right)

⇒\Rightarrow 23=(21)2(M1M2){2 \over 3} = {\left( {{2 \over 1}} \right)^2}\left( {{{{M_1}} \over {{M_2}}}} \right)

⇒\Rightarrow M1M2{{{{M_1}} \over {{M_2}}}} = 16{1 \over 6}

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