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QJEEM20Phcb83: JEE Main 2020 Physics - Class 12 JEEM20Phcb83 Solution: A particle of mass m and charge q has an initial velocity v → = …

A particle of mass m and charge q has an initial velocity v→=v0j^ . If an electric field E→=E0i^ and magnetic field B→=B0i^ act on the particle, its speed will double after a time:

Multiple Choice Options

  • A 3mv0qE0
  • B 2mv0qE0
  • C 3mv0qE0
  • D 2mv0qE0

Step-by-Step Verified Solution

Electric field will increase the speed of particle in x direction.

Fx = qE

∴ a = qEm

Also vx = at = qEmt

vx2+vy2=v2

⇒ vx2+v02=(2v0)2

⇒ vx = 3v0

∴ qEmt = 3v0

⇒ t = 3mv0qE0

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