Verified Solution • 2025–26 Session moderate

QJEEM20Phc1d9: JEE Main 2020 Physics - Class 11 JEEM20Phc1d9 Solution: A cube of metal is subjected to a hydrostatic pressure of 4…

A cube of metal is subjected to a hydrostatic pressure of 4 GPa. The percentage change in the length of the side of the cube is close to :
(Given bulk modulus of metal, B = 8 ×\times 1010 Pa)

Multiple Choice Options

  • A 0.6
  • B 20
  • C 1.67
  • D 5

Step-by-Step Verified Solution

Bulk Modulus, B = (−)ΔPΔV/V\left( - \right){{\Delta P} \over {\Delta V/V}}

ΔP=−(ΔVV).B\Delta P = -\left( {{{\Delta V} \over V}} \right).B

=−3ΔLL×B= -{{3\Delta L} \over L} \times B

∴\therefore ∣ΔLL∣=ΔP3B|{{\Delta L} \over L}| = {{\Delta P} \over {3B}}

∴\therefore % change, ΔLL×100%{{\Delta L} \over L} \times 100\%

= 13ΔPB×100{1 \over 3}{{\Delta P} \over B} \times 100

= 4×1098×1010×100{{4 \times {{10}^9}} \over {8 \times {{10}^{10}}}} \times 100

= 160×100{1 \over {60}} \times 100 = 1.67

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