Verified Solution • 2025–26 Session moderate

QJEEM20Phbcde: JEE Main 2020 Physics - Class 11 JEEM20Phbcde Solution: Dimensional formula for thermal conductivity is (here K denotes …

Dimensional formula for thermal conductivity is (here K denotes the temperature):

Multiple Choice Options

  • A MLT–3K–1
  • B MLT–2K–2
  • C MLT–2K
  • D MLT–3K

Step-by-Step Verified Solution

∴\therefore dθdt=kAdTdx{{d\theta } \over {dt}} = kA{{dT} \over {dx}}

⇒\Rightarrow k = (dθdt)A(dTdx){{\left( {{{d\theta } \over {dt}}} \right)} \over {A\left( {{{dT} \over {dx}}} \right)}}

⇒\Rightarrow [k] = [ML2T−3][L2][KL−1]{{\left[ {M{L^2}{T^{ - 3}}} \right]} \over {\left[ {{L^2}} \right]\left[ {K{L^{ - 1}}} \right]}}

= [MLT–3K–1]

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