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QJEEM20Phb66c: JEE Main 2020 Physics - Class 12 JEEM20Phb66c Solution: The current i in the network is :

The current i in the network is : JEE Main 2020 (Online) 9th January Evening Slot Physics - Semiconductor Question 142 English

Multiple Choice Options

  • A 0.6 A
  • B 0.3 A
  • C 12:00 AM
  • D 0.2 A

Step-by-Step Verified Solution

Both the diodes are reverse biased. JEE Main 2020 (Online) 9th January Evening Slot Physics - Semiconductor Question 142 English Explanation

i = 95+10+5+10{9 \over {5 + 10 + 5 + 10}} = 930{9 \over {30}} A

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