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QJEEM20Phaa2b: JEE Main 2020 Physics - Class 12 JEEM20Phaa2b Solution: A charged particle carrying charge 1 μ C is moving with…

A charged particle carrying charge 1 μC is moving
with velocity (2i^+3j^+4k^) ms–1. If an external
magnetic field of (5i^+3j^−6k^)× 10–3 T exists in the region where the particle is moving then the
force on the particle is F→ × 10–9 N. The vector F→ is :

Multiple Choice Options

  • A −0.30i^+0.32j^−0.09k^
  • B −300i^+320j^−90k^
  • C −30i^+32j^−9k^
  • D −3.0i^+3.2j^−0.9k^

Step-by-Step Verified Solution

Given,

V→ = (2i^+3j^+4k^) ms–1

B→ = (5i^+3j^−6k^)× 10–3 T

q = 1 μC

F→=q(V→×B→)

= 10−6×10−3×|i^j^k^23453−6|

= (−30i^+32j^−9k^) × 10-9

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