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QJEEM20Pha77f: JEE Main 2020 Physics - Class 12 JEEM20Pha77f Solution: An infinitely long, straight wire carrying current I, one side…

An infinitely long, straight wire carrying current I, one side opened rectangular loop and a conductor C with a sliding connector are located in the same plane, as shown, in the figure. The connector has length ll and resistance R. It slides to the right with a velocity v. The resistance of the conductor and the self inductance of the loop are negligible. The induced current in the loop, as a function of separation r, between the connector and the straight wire is : JEE Main 2020 (Online) 5th September Evening Slot Physics - Electromagnetic Induction Question 81 English

Multiple Choice Options

  • A μ04πIvlRr{{{\mu _0}} \over {4\pi }}{{Ivl} \over {Rr}}
  • B μ0πIvlRr{{{\mu _0}} \over {\pi }}{{Ivl} \over {Rr}}
  • C μ02πIvlRr{{{\mu _0}} \over {2\pi }}{{Ivl} \over {Rr}}
  • D 2μ0πIvlRr{{2{\mu _0}} \over \pi }{{Ivl} \over {Rr}}

Step-by-Step Verified Solution

B = (μ0I2πr)\left( {{{{\mu _0}I} \over {2\pi r}}} \right)

induced current i = eR=BvlR{e \over R} = {{Bvl} \over R}

= (μ0I2πr)vlR\left( {{{{\mu _0}I} \over {2\pi r}}} \right){{vl} \over R}

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