Verified Solution • 2025–26 Session moderate

QJEEM20Pha699: JEE Main 2020 Physics - Class 11 JEEM20Pha699 Solution: A body is moving in a low circular orbit about a planet of mass …

A body is moving in a low circular orbit about a planet of mass M and radius R. The radius of the orbit can be taken to be R itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is:

Multiple Choice Options

  • A 2
  • B 1
  • C 2\sqrt 2
  • D 12{1 \over {\sqrt 2 }}

Step-by-Step Verified Solution

V0=GMr{V_0} = \sqrt {{{GM} \over r}}

Ve=2GMr{V_e} = \sqrt {{{2GM} \over r}}

∴\therefore V0Ve=GMr×2GMr=12{{{V_0}} \over {{V_e}}} = \sqrt {{{GM} \over r} \times {{2GM} \over r}} = {1 \over {\sqrt 2 }}

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