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QJEEM20Pha5fc: JEE Main 2020 Physics - Class 11 JEEM20Pha5fc Solution: An massless equilateral triangle EFG of side ‘a’ (As shown in…

An massless equilateral triangle EFG of side ‘a’ (As shown in figure) has three particles of mass m situated at its vertices. The moment of inertia of the system about the line EX perpendicular to EG in the plane of EFG is N20{N \over {20}} ma2 where N is an integer. The value of N is _____. JEE Main 2020 (Online) 3rd September Evening Slot Physics - Rotational Motion Question 128 English

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JEE Main 2020 (Online) 3rd September Evening Slot Physics - Rotational Motion Question 128 English Explanation
I = m aa 2 + ma24{{m{a^2}} \over 4} = 54ma2{5 \over 4}m{a^2}

Accoeding to the question,

54ma2=N20ma2{5 \over 4}m{a^2} = {N \over {20}}m{a^2}

⇒\Rightarrow N = 25

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