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QJEEM20Pha147: JEE Main 2020 Physics - Class 11 JEEM20Pha147 Solution: The acceleration due to gravity on the earth’s surface at the…

The acceleration due to gravity on the earth’s surface at the poles is g and angular velocity of the earth about the axis passing through the pole is ω. An object is weighed at the equator and at a height h above the poles by using a spring balance. If the weights are found to be same, then h is (h << R, where R is the radius of the earth)

Multiple Choice Options

  • A R2ω22g
  • B R2ω2g
  • C R2ω28g
  • D R2ω24g

Step-by-Step Verified Solution

At equator, g1 = g - Rω2

At height h, g2 = g(1−2hR) [as given h << R]

∵ Weight same at poles and at h (so g1 = g2)

∴ g - Rω2 = g(1−2hR)

⇒ Rω2=2ghR

⇒ h=R2ω22g

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