Verified Solution • 2025–26 Session moderate

QJEEM20Ph9791: JEE Main 2020 Physics - Class 11 JEEM20Ph9791 Solution: A student measuring the diameter of a pencil of circular…

A student measuring the diameter of a pencil of circular cross-section with the help of a vernier scale records the following four readings 5.50 mm, 5.55 mm, 5.45 mm, 5.65 mm. The average of these four readings is 5.5375 mm and the standard deviation of the data is 0.07395 mm. The average diameter
of the pencil should therefore be recorded as :

Multiple Choice Options

  • A (5.54 ± 0.07) mm
  • B (5.5375 ± 0.0740) mm
  • C (5.5375 ± 0.0739) mm
  • D (5.538 ± 0.074) mm

Step-by-Step Verified Solution

Given, dav = 5.5375 mm

Δd = 0.07395 mm

Significant rule says that reading should has same significant figure as that of reading given.

∵ Measured data are up to two digits after decimal.

∴ 5.5375 rounded to → 5.54

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