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QJEEM20Ph8ece: JEE Main 2020 Physics - Class 12 JEEM20Ph8ece Solution: Four resistances of 15 Ω , 12 Ω , 4 Ω and 10 Ω respectively in…

Four resistances of 15Ω, 12Ω, 4Ω and 10Ω respectively in cyclic order to form Wheatstone's network. The resistance that is to be connected in parallel with the resistance of 10Ω to balance the network is _____Ω.

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JEE Main 2020 (Online) 8th January Morning Slot Physics - Current Electricity Question 225 English Explanation

Wheatstone bridge balance condition

R1R2=R3R4

⇒ 154=1510R10+R

⇒ 2R = 10 + R

⇒ R = 10 Ω

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