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QJEEM20Ph8b40: JEE Main 2020 Physics - Class 12 JEEM20Ph8b40 Solution: Given figure shows few data points in a phot electric effect…
Given figure shows few data points in a phot electric effect experiment for a certain metal. The minimum energy for ejection of electron from its surface is:
(Plancks constant h = 6.62 × 10–34 J.s)
(Plancks constant h = 6.62 × 10–34 J.s)
Multiple Choice Options
- A 2.10 eV
- B 2.27 eV
- C 2.59 eV
- D 1.93 eV
Step-by-Step Verified Solution
Kmax = hf -
at B V0 = 0, f = 5.5
=
=
= 2.27 eV
at B V0 = 0, f = 5.5
=
=
= 2.27 eV