QJEEM20Ph86a0: JEE Main 2020 Physics - Class 12 JEEM20Ph86a0 Solution: If a semiconductor photodiode can detect a photon with a…

Question

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If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is :

Planck’s constant h = 6.63

\times

10^–34 J.s. Speed of light c = 3

\times

10⁸ m/s

Accepted Answer

E = \frac{h c}{λ}

=

\frac{6.63 \times 10^{- 34} \times 3 \times 10^{8}}{400 \times 10^{- 9}}

=

\frac{1240}{400}

eV

= 3.1 eV

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