Verified Solution • 2025–26 Session moderate

QJEEM20Ph866f: JEE Main 2020 Physics - Class 11 JEEM20Ph866f Solution: Pressure inside two soap bubbles are 1.01 and 1.02 atmosphere,…

Pressure inside two soap bubbles are 1.01 and 1.02 atmosphere, respectively. The ratio of their volumes is :

Multiple Choice Options

  • A 4:01
  • B 8:01
  • C 2:01
  • D 0.8 : 1

Step-by-Step Verified Solution

Pin=P0+4TR1{P_{in}} = {P_0} + {{4T} \over {{R_1}}}

⇒1.01=1+4TR1\Rightarrow 1.01 = 1 + {{4T} \over {{R_1}}}

⇒4TR1=0.01\Rightarrow {{4T} \over {{R_1}}} = 0.01

1.02=1+4TR21.02 = 1 + {{4T} \over {{R_2}}}

⇒4TR2=0.02\Rightarrow {{4T} \over {{R_2}}} = 0.02

∴R2R1=12\therefore {{{R_2}} \over {{R_1}}} = {1 \over 2}

⇒R1=2R2\Rightarrow {R_1} = 2{R_2}

V1V2=R13R23=8R23R23=81{{{V_1}} \over {{V_2}}} = {{R_1^3} \over {R_2^3}} = {{8R_2^3} \over {R_2^3}} = {8 \over 1}

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