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QJEEM20Ph7e81: JEE Main 2020 Physics - Class 11 JEEM20Ph7e81 Solution: Two moles of an ideal gas with are mixed with 3 moles of…

Two moles of an ideal gas with CPCV=53{{{C_P}} \over {{C_V}}} = {5 \over 3} are mixed with 3 moles of another ideal gas with CPCV=43{{{C_P}} \over {{C_V}}} = {4 \over 3} . The value of CPCV{{{C_P}} \over {{C_V}}} for the mixture is :

Multiple Choice Options

  • A 1.5
  • B 1.45
  • C 1.47
  • D 1.42

Step-by-Step Verified Solution

Cp = n1Cp1+n2Cp2n1+n2{{{n_1}{C_{{p_1}}} + {n_2}{C_{{p_2}}}} \over {{n_1} + {n_2}}}

Cv = n1CV1+n2CV2n1+n2{{{n_1}{C_{{V_1}}} + {n_2}{C_{{V_2}}}} \over {{n_1} + {n_2}}}

γ\gamma mix = CpCv{{{C_p}} \over {{C_v}}} = 2×52R+3×82R2×32R+3×62R{{2 \times {5 \over 2}R + 3 \times {8 \over 2}R} \over {2 \times {3 \over 2}R + 3 \times {6 \over 2}R}}

= 5+123+9{{5 + 12} \over {3 + 9}} = 1.42

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