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QJEEM20Ph7b79: JEE Main 2020 Physics - Class 11 JEEM20Ph7b79 Solution: A particle of mass m is fixed to one end of a light spring…

A particle of mass m is fixed to one end of a light spring having force constant k and unstretched length ℓ. The other end is fixed. The system is given an angular speed ω about the fixed end of the spring such that it rotates in a circle in gravity free space. Then the stretch in the spring is :

Multiple Choice Options

  • A mℓω2k−mω2
  • B mℓω2k−mω
  • C mℓω2k+mω2
  • D mℓω2k+mω

Step-by-Step Verified Solution

JEE Main 2020 (Online) 8th January Morning Slot Physics - Circular Motion Question 56 English Explanation
At elongated position (x),

Fradial = mrω2

∴ kx = m(l+x)ω2

⇒ x = mℓω2k−mω2

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