QJEEM20Ph7932: JEE Main 2020 Physics - Class 12 JEEM20Ph7932 Solution: In LC circuit the inductance L = 40 mH and capacitance C = 100…

Question

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In LC circuit the inductance L = 40 mH and
capacitance C = 100

μ

F. If a voltage
V(t) = 10sin(314t) is applied to the circuit, the
current in the circuit is given as :

Accepted Answer

Z = x_C – x_L

=

\frac{1}{ω C} - ω L

=

\frac{1}{314 \times 100 \times 10^{- 6}} - 314 \times 40 \times 10^{- 3}

= 19.28

Ω

As V_m = I_mZ

\Rightarrow

10 = I_m

\times

19.28

\Rightarrow

I_m =

\frac{10}{19.28}

= 0.52 A

∴

I = 0.52 sin(314t +

\frac{π}{2}

)

= 0.52 cos(314t)

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