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QJEEM20Ph71d2: JEE Main 2020 Physics - Class 12 JEEM20Ph71d2 Solution: In a fluorescent lamp choke (a small transformer) 100 V of…

In a fluorescent lamp choke (a small transformer) 100 V of reverse voltage is produced when the choke current changes uniformly from 0.25 A to 0 in a duration of 0.025 ms. The self-inductance of the choke (in mH) is estimated to be ________.

Step-by-Step Verified Solution

V = ∣Ldidt∣\left| {L{{di} \over {dt}}} \right|

⇒\Rightarrow L = V∣didt∣{V \over {\left| {{{di} \over {dt}}} \right|}} = 1000.250.025×10−3{{100} \over {{{0.25} \over {0.025 \times {{10}^{ - 3}}}}}} = 10 mH

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