QJEEM20Ph6f6b: JEE Main 2020 Physics - Class 11 JEEM20Ph6f6b Solution: The dimension of B 2 2 μ 0 , where B is magnetic field and μ 0…

Question

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The dimension of

\frac{B^{2}}{2 μ_{0}}

, where B is magnetic field and

μ_{0}

is the magnetic permeability of vacuum, is :

Accepted Answer

As

\frac{B^{2}}{2 μ_{0}}

= Energy per unit volume

∴

Dimension =

\frac{M L^{2} T^{- 2}}{L^{3}}

= ML^-1T^–2

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