QJEEM20Ph6ce4: JEE Main 2020 Physics - Class 12 JEEM20Ph6ce4 Solution: The graph which depicts the results of Rutherford gold foil…

Question

Verified Solution • 2025–26 Session moderate

The graph which depicts the results of Rutherford gold foil experiment with

α

-particales is :

θ

: Scattering angle
Y : Number of scattered

α

-particles detected (Plots are schematic and not to scale)

A https://ik.imagekit.io/novatra/photos/8e22db273cf96e0b0708a6cfa1d0844699adeebf09a169f4e8a53b053018aa36.webp
B https://ik.imagekit.io/novatra/photos/8cfdab09eceb7fdbfc179464e732d64c6ee752ad9e4cbf4272d04330ad1a0c90.webp
C https://ik.imagekit.io/novatra/photos/a7f95792dd52a710f512f76dad079bb6d3f74ef07f28d3b15f15dc71d12d0c82.webp
D https://ik.imagekit.io/novatra/photos/40703eb51d9d87406ff91873a7023e8a208a238167a5c9cffa4759f98bd0e74c.webp

Accepted Answer

From Ernest Rutherford formula. Which indicates that number of particles (Y) that would be deflected by an angle ‘

θ

’ due to scattering is

Y_{θ} = \frac{K}{\sin^{4} \frac{θ}{2}}

where K = constant

Option (C) is the correct answer.

Step-by-Step Verified Solution