QJEEM20Ph6c51: JEE Main 2020 Physics - Class 12 JEEM20Ph6c51 Solution: In a reactor, 2 kg of 92 U 235 fuel is fully used up in 30…

Number of uranium atoms in 2 kg

= $$\frac{2\times 6.023\times {10}^{26}}{235}$$

Energy from one atom is 200 × 10⁶ e.V. hence total energy from 2 kg uranium

= $$\frac{2\times 6.023\times {10}^{26}}{235}\times 200\times {10}^6$$ eV

= $$\frac{2\times 6.023\times {10}^{26}}{235}\times 200\times {10}^6$$ $$\times$$ 1.6 × 10^–19 J

2 kg uranium is used in 30 days hence energy received per second or power is

Power = $$\frac{2\times 6.023\times {10}^{26}\times 200\times {10}^6\times 1.6\times {10}^{-19}}{235\times 30\times 24\times 3600}$$

= 63.2 × 10⁶ watt or 63.2 Mega Watt

$$\simeq$$ 60 MW