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QJEEM20Ph69da: JEE Main 2020 Physics - Class 12 JEEM20Ph69da Solution: Orange light of wavelength 6000 10 –10 m illuminates a single…

Orange light of wavelength 6000 ×\times 10–10 m illuminates a single
slit of width 0.6 ×\times 10–4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is ___________.

Step-by-Step Verified Solution

For minima

d sin⁡θ=nλd\,\sin \theta = n\lambda

or sin⁡θ=nλd\sin \theta = {{n\lambda } \over d}

∵\because maximum value of sin θ\theta is 1

∴\therefore nλd≤1{{n\lambda } \over d} \le 1

n≤dλn \le {d \over \lambda }

n≤0.6×10−46000×10−10n \le {{0.6 \times {{10}^{ - 4}}} \over {6000 \times {{10}^{ - 10}}}}

n≤100n \le 100

For both sides 100 + 100 = 200

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