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QJEEM20Ph674f: JEE Main 2020 Physics - Class 11 JEEM20Ph674f Solution: Consider a force . The work done by this force in moving a…

Consider a force F→=−xi^+yj^\overrightarrow F = - x\widehat i + y\widehat j . The work done by this force in moving a particle from point A(1, 0) to B(0, 1) along the line segment is : (all quantities are in SI units) JEE Main 2020 (Online) 9th January Morning Slot Physics - Work Power & Energy Question 93 English

Multiple Choice Options

  • A 2
  • B 12{1 \over 2}
  • C 1
  • D 32{3 \over 2}

Step-by-Step Verified Solution

W = ∫F→.dr→\int {\overrightarrow F } .d\overrightarrow r

= ∫(−xi^+yj^).(dxi^+dyj^)\int {\left( { - x\widehat i + y\widehat j} \right)} .\left( {dx\widehat i + dy\widehat j} \right)

= −∫10xdx+∫01ydy- \int\limits_1^0 {xdx} + \int\limits_0^1 {ydy}

= 12+12{1 \over 2} + {1 \over 2} = 1 J

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