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QJEEM20Ph61d5: JEE Main 2020 Physics - Class 12 JEEM20Ph61d5 Solution: The circuit shown below is working as a 8 V dc regulated…

The circuit shown below is working as a 8 V dc regulated voltage source. When 12 V is used as input, the power dissipated (in mW) in each diode is; (considering both zener diodes are identical) _________. JEE Main 2020 (Online) 9th January Evening Slot Physics - Semiconductor Question 140 English

Step-by-Step Verified Solution

Current in circuit = 12−8200+200{{12 - 8} \over {200 + 200}} = 10-2 A

So power dissipited in each diode = VI

= 4 ×\times 10-2

= 40 mW

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