QJEEM20Ph60c3: JEE Main 2020 Physics - Class 11 JEEM20Ph60c3 Solution: A quantity x is given by in terms of moment of inertia I, force …

Question

Verified Solution • 2025–26 Session moderate

A quantity x is given by

\left( {{{IF{v^2}} \over {W{L^4}}}} \right)

in terms of moment of inertia I, force F, velocity v, work W and Length L. The dimensional formula for x is same as that of :

Accepted Answer

x =

\left( {{{IF{v^2}} \over {W{L^4}}}} \right)

\therefore

[x] =

{{\left[ {M{L^2}} \right]\left[ {ML{T^{ - 2}}} \right]{{\left[ {L{T^{ - 1}}} \right]}^2}} \over {\left[ {M{L^2}{T^{ - 2}}} \right]{{\left[ L \right]}^4}}}

= [ML^-1T^-2]

= [Energy density]

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