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QJEEM20Ph601b: JEE Main 2020 Physics - Class 12 JEEM20Ph601b Solution: Charges Q 1 and Q 2 are at points A and B of a right angle…

Charges Q1 and Q2 are at points A and B of a right angle triangle OAB (see figure). The resultant electric field at point O is perpendicular to the hypotenuse, then
Q1Q2 is proportional to : JEE Main 2020 (Online) 6th September Morning Slot Physics - Electrostatics Question 146 English

Multiple Choice Options

  • A x13x23
  • B x22x12
  • C x1x2
  • D x2x1

Step-by-Step Verified Solution

JEE Main 2020 (Online) 6th September Morning Slot Physics - Electrostatics Question 146 English Explanation

Net field along AB at O must be zero.

E1sinθ = E2cos θ

⇒ kQ1x12.x1AB = kQ2x22.x2AB

⇒ Q1Q2=x1x2

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