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QJEEM20Ph5f76: JEE Main 2020 Physics - Class 11 JEEM20Ph5f76 Solution: Nitrogen gas is at 300 o C temperature. The temperature (in K)…

Nitrogen gas is at 300oC temperature. The temperature (in K) at which the rms speed of a H2 molecule would be equal to the rms speed of a nitrogen molecule, is _______.
(Molar mass of N2 gas 28 g).

Step-by-Step Verified Solution

Vrms = 3RTM\sqrt {{{3RT} \over M}}

VN2 = 3R(573)28\sqrt {{{3R(573)} \over 28}}

VH2 = 3RT2\sqrt {{{3RT} \over 2}}

Given, VN2 = VH2

3RT2\sqrt {{{3RT} \over 2}} = 3R(573)28\sqrt {{{3R(573)} \over 28}}

⇒\Rightarrow T2=57328{T \over 2} = {{573} \over {28}}

⇒\Rightarrow T = 41 K

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