QJEEM20Ph5f0c: JEE Main 2020 Physics - Class 11 JEEM20Ph5f0c Solution: Two gases-argon (atomic radius 0.07 nm, atomic weight 40) and…

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QJEEM20Ph5f0c: JEE Main 2020 Physics - Class 11 JEEM20Ph5f0c Solution: Two gases-argon (atomic radius 0.07 nm, atomic weight 40) and…

Two gases-argon (atomic radius 0.07 nm, atomic weight 40) and xenon (atomic radius 0.1 nm, atomic weight 140) have the same number density and are at the same temperature. The raito of their respective mean free times is closest to :

Multiple Choice Options

A 2.3
B 1.83
C 4.67
D 3.67

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Accepted Answer

λ = \frac{1}{\sqrt{2} π d^{2} n}

Mean free time, t =

\frac{λ}{v}

Also v

\propto

\sqrt{\frac{T}{M}}

∴

t

\propto

\frac{\sqrt{M}}{d}

\frac{t_{A r}}{t_{x e}}

=

\frac{d_{X e}^{2}}{d_{A r}^{2}} \times \sqrt{\frac{M_{A r}}{M_{X e}}}

=

{(\frac{0.1}{0.07})}^{2} \times \sqrt{\frac{40}{140}}

= 1.09

∴

Nearest possible answer is 1.83.

QJEEM20Ph5f0c: JEE Main 2020 Physics - Class 11 JEEM20Ph5f0c Solution: Two gases-argon (atomic radius 0.07 nm, atomic weight 40) and…

Multiple Choice Options

Step-by-Step Verified Solution

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