Verified Solution • 2025–26 Session moderate

QJEEM20Ph58b9: JEE Main 2020 Physics - Class 12 JEEM20Ph58b9 Solution: An electron, a doubly ionized helium ion (He ++ ) and a proton…

An electron, a doubly ionized helium ion (He++) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths λe, λHe++ and λp is :

Multiple Choice Options

  • A λe > λHe++ > λp
  • B λe < λp < λHe++
  • C λe > λp > λHe++
  • D λe < λHe++ = λp

Step-by-Step Verified Solution

λ = hP = h2m(KE)

∴ λ ∝ 1m

mHe++ > mp > me

∴ λe > λp > λHe++

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