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QJEEM20Ph51b5: JEE Main 2020 Physics - Class 12 JEEM20Ph51b5 Solution: Two Zener diodes (A and B) having breakdown voltages of 6 V and …

Two Zener diodes (A and B) having breakdown voltages of 6 V and 4 V respectively, are connected as shown in the circuit below. The output voltage V0 variation with input voltage linearly increasing with time, is given by :
(Vinput = 0 V at t = 0)
(figures are qualitative) JEE Main 2020 (Online) 5th September Evening Slot Physics - Semiconductor Question 132 English

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/5dbb1c35757288f47d4cffd2630d524b5c03061ea5698bd16e9a86283432c6ea.webp
  • B https://ik.imagekit.io/novatra/photos/b3c597e27356b3ce1e1e6c0f1e4fd59590f2e77b7e38e540792ae3edae28d5a9.webp
  • C https://ik.imagekit.io/novatra/photos/5f0000660719d96c0f7fdf1fa3400efebe66ee67d2c21cf76de4ed20f59daaa4.webp
  • D https://ik.imagekit.io/novatra/photos/d9ba7faadd11753541ecdbf26b2807a6bd0598040e17fec78190835841847660.webp

Step-by-Step Verified Solution

Till input voltage reaches 4V, both diode will stay deactvated so output voltage will be same as input voltage.

When input voltage reach 4V, then 4V diode will get activated and it will transfer only 4V to the output but as a rasistance is present in series with the 4V diode so some voltage drop will happen across the resistor. So output
voltage(Vo) will be = 4V + voltage drop.

When input voltage reach 6V, then 6V diode will get activated and it will transfer only 6V to the output no matter how much input voltage become.

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