Verified Solution • 2025–26 Session moderate

QJEEM20Ph372e: JEE Main 2020 Physics - Class 12 JEEM20Ph372e Solution: Two charged thin infinite plane sheets of uniform surface…

Two charged thin infinite plane sheets of
uniform surface charge density σ+{\sigma _ + } and σ−{\sigma _ - } ,
where | σ+{\sigma _ + } | > | σ−{\sigma _ - } |, intersect at right angle.
Which of the following best represents the
electric field lines for this system :

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/5f773b66d0477c3a3082fca3ee1ec5705482d8e15cf54429f267779e15351759.webp
  • B https://ik.imagekit.io/novatra/photos/4d16b3d6a3fc67036abb66f20e5ee7771b23a48a6f7222540de4e5dbba7b4ee0.webp
  • C https://ik.imagekit.io/novatra/photos/eda4b213557aaa2cec1798841fc6535708f51fffdc74c5a91db30d934061a1da.webp
  • D https://ik.imagekit.io/novatra/photos/998401a9d99a658a4846cc482137cf6c50507110ac36c080a866e7da8382cc6c.webp

Step-by-Step Verified Solution

JEE Main 2020 (Online) 4th September Morning Slot Physics - Electrostatics Question 156 English Explanation Given, | σ+{\sigma _ + } | > | σ−{\sigma _ - } |

We know, ∣E+∣=∣σ+∣ε0\left| {{E_ + }} \right| = {{\left| {{\sigma _ + }} \right|} \over {{\varepsilon _0}}}

and ∣E−∣=∣σ−∣ε0\left| {{E_ - }} \right| = {{\left| {{\sigma _ - }} \right|} \over {{\varepsilon _0}}}

∴\therefore ∣E+∣\left| {{E_ + }} \right| > ∣E−∣\left| {{E_ - }} \right|

Thin infinite uniformly charged planes produces uniform electric field therefore option A and C are obviously wrong.

And as positive charge density is bigger in magnitude so its field along Y direction will be bigger than field of negative charge in X direction and this is evident in option B so it is correct.

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