Verified Solution • 2025–26 Session moderate

QJEEM20Ph26d1: JEE Main 2020 Physics - Class 12 JEEM20Ph26d1 Solution: An amplitude modulated wave is represented by the expression v…

An amplitude modulated wave is represented by the expression
vm = 5(1 + 0.6 cos 6280t) sin(211 × 104 t) volts
The minimum and maximum amplitudes of the amplitude modulated wave are, respectively

Multiple Choice Options

  • A 32 V, 5 V
  • B 52 V, 8 V
  • C 5 V, 8 V
  • D 3 V, 5 V

Step-by-Step Verified Solution

vm = 5(1 + 0.6 cos 6280t) sin(211 × 104 t)

⇒ vm = (5 + 3 cos 6280t) sin(211 × 104 t)

maximum Amp. = 5 + 3 = 8 V

minimum Amp. = 5 – 3 = 2 V

From the given option nearest value of minimum Amplitude = 52 V

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