QJEEM20Ph1e92: JEE Main 2020 Physics - Class 11 JEEM20Ph1e92 Solution: Starting from the origin at time t = 0, with initial velocity 5 …

Question

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Starting from the origin at time t = 0, with initial velocity 5

\hat{j}

ms^-1 , a particle moves in the x-y plane with a constant acceleration of

(10 \hat{i} + 4 \hat{j})

ms^-2. At time t, its coordinates are (20 m, y₀ m). The values of t and y₀ are, respectively:

Accepted Answer

y = u_{y} t + \frac{1}{2} a_{y} t^{2}

y = 5 t + \frac{1}{2} (4) t^{2}

y = 5 t + 2 t^{2}

and

x = 0 (t) + \frac{1}{2} (10) (t^{2}) = 20

t = 2 s

\Rightarrow y = 10 + 8 = 18 m

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