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QJEEM20Ph16e4: JEE Main 2020 Physics - Class 11 JEEM20Ph16e4 Solution: A uniform sphere of mass 500 g rolls without slipping on a…

A uniform sphere of mass 500 g rolls without slipping on a plane horizontal surface with its centre moving at a speed of 5.00 cm/s. Its kinetic energy is :

Multiple Choice Options

  • A 8.75 × 10–3 J
  • B 1.13 × 10–3 J
  • C 8.75 × 10–4 J
  • D 6.25 × 10–4 J

Step-by-Step Verified Solution

K.E = 12mV2+12Icmω2{1 \over 2}m{V^2} + {1 \over 2}{I_{cm}}{\omega ^2}

= 12mV2+12×25mR2×V2R2{1 \over 2}m{V^2} + {1 \over 2} \times {2 \over 5}m{R^2} \times {{{V^2}} \over {{R^2}}}

= 12mV2+15mV2{1 \over 2}m{V^2} + {1 \over 5}m{V^2}

= 710mV2{7 \over {10}}m{V^2}

= 710×0.5×25×10−4{7 \over {10}} \times 0.5 \times 25 \times {10^{ - 4}}

= 354×10−4{{35} \over 4} \times {10^{ - 4}}

= 8.75 × 10–4 J

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