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QJEEM20Ph13ce: JEE Main 2020 Physics - Class 11 JEEM20Ph13ce Solution: Two particles of equal mass m have respective initial…

Two particles of equal mass m have respective
initial velocities ui^u\widehat i and u(i^+j^2)u\left( {{{\widehat i + \widehat j} \over 2}} \right) .
They collide completely inelastically. The energy lost in the process is :

Multiple Choice Options

  • A 13mu2{1 \over 3}m{u^2}
  • B 18mu2{1 \over 8}m{u^2}
  • C 34mu2{3 \over 4}m{u^2}
  • D 23mu2\sqrt {{2 \over 3}} m{u^2}

Step-by-Step Verified Solution

Pi→=Pf→\overrightarrow {{P_i}} = \overrightarrow {{P_f}}

⇒\Rightarrow mu i^\widehat i + m (u2i^+u2j^)\left( {{u \over 2}\widehat i + {u \over 2}\widehat j} \right) = 2m v→\overrightarrow v

Compare both side

v→=\overrightarrow v = 3u4i^+u4j^{{3u} \over 4}\widehat i + {u \over 4}\widehat j

⇒\Rightarrow ∣v→∣2{\left| {\overrightarrow v } \right|^2} = 10u216{{10{u^2}} \over {16}}

Δ\Delta KE = KEf – KEi

= 122m×10u216{1 \over 2}2m \times {{10{u^2}} \over {16}} - 12mu2{1 \over 2}m{u^2} - 12m(u2)2{1 \over 2}m{\left( {{u \over {\sqrt 2 }}} \right)^2}

= −18mu2- {1 \over 8}m{u^2}

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