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QJEEM20Ph0f2a: JEE Main 2020 Physics - Class 11 JEEM20Ph0f2a Solution: A thin rod of mass 0.9 kg and length 1 m is suspended, at rest, …
A thin rod of mass 0.9 kg and length 1 m is suspended, at rest, from one end so that it can freely oscillate in the vertical plane. A particle of move 0.1 kg moving in a straight line with velocity 80 m/s hits the rod at its bottom most point and sticks to it (see figure). The angular speed (in rad/s) of the rod immediately after the collision will be _________.
Step-by-Step Verified Solution
The given situation is shown in the following figure,

Applying law of conservation of angular momentum about pivotal point,
Given, m = 0.1 kg, v = 80 ms
Substituting these values in eq. (i), we get