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QJEEM20Ph0dd7: JEE Main 2020 Physics - Class 12 JEEM20Ph0dd7 Solution: The magnifying power of a telescope with tube 60 cm is 5. What…

The magnifying power of a telescope with tube 60 cm is 5. What is the focal length of its eye piece ?

Multiple Choice Options

  • A 40 cm
  • B 10 cm
  • C 30 cm
  • D 20 cm

Step-by-Step Verified Solution

For telescope

Tube length (L) = f0 + fe

and magnification (m) = f0fe{{{f_0}} \over {{f_e}}} = 5

where fo and fe are focal length of objective and eyepiece.

∴\therefore f0 + fe = 60

∴\therefore fo = 50 cm

fe = 10 cm

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