Verified Solution • 2025–26 Session moderate

QJEEM20Ph022c: JEE Main 2020 Physics - Class 12 JEEM20Ph022c Solution: If the magnetic field in a plane electromagnetic wave is given…

If the magnetic field in a plane electromagnetic wave is given by
B→ = 3 × 10-8 sin(1.6 × 103x + 48 × 1010t)j^ T, then what will be expression for electric field ?

Multiple Choice Options

  • A E→ = (9sin(1.6 × 103x + 48 × 1010t)k^ V/m)
  • B E→ = (60sin(1.6 × 103x + 48 × 1010t)k^ V/m)
  • C E→ = (3 × 10-8 sin(1.6 × 103x + 48 × 1010t)i^ V/m)
  • D E→ = (3 × 10-8 sin(1.6 × 103x + 48 × 1010t)j^ V/m)

Step-by-Step Verified Solution

Given B→ = 3 × 10-8 sin(1.6 × 103x + 48 × 1010t)j^ T

We know, E0B0=c

⇒ E0 = (3 × 10-8) × (3 × 10-8) = 9 V/m

∴ E→ = (9sin(1.6 × 103x + 48 × 1010t)k^ V/m)

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