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QJEEM20Ph0012: JEE Main 2020 Physics - Class 12 JEEM20Ph0012 Solution: Two sources of light emit X-rays of wavelength 1 nm and visible …

Two sources of light emit X-rays of wavelength 1 nm and visible light of wavelength 500 nm, respectively. Both the sources emit light of the same power 200 W. The ratio of the number density of photons of X-rays to the number density of photons of the visible light of the given wavelengths is :

Multiple Choice Options

  • A 1500
  • B 500
  • C 250
  • D 1250

Step-by-Step Verified Solution

Given, wavelength of x ray (λ1) = 1 nm

And wavelength of visible light (λ2) = 500 nm

we know, Power(P)=nhcλ

As P = constant and h, c also constant

So, nλ=constant

⇒ n1n2=λ1λ2=1nm500nm=1500

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