QJEEM20Mae8ba: JEE Main 2020 Mathematics - Class 11 JEEM20Mae8ba Solution: Let two points be A(1, –1) and B(0, 2). If a point P(x', y') be …

Question

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Let two points be A(1, –1) and B(0, 2). If a point P(x', y') be such that the area of

\Delta

PAB = 5 sq. units and it lies on the line, 3x + y – 4

\lambda

= 0, then a value of

\lambda

is :

Accepted Answer

Point P(x', y') lies on the line 3x + y – 4

\lambda

= 0

\therefore

3x' + y' – 4

\lambda

= 0

Area of

\Delta

PAB = 5

\Rightarrow

\frac{1}{2} | \begin{matrix} 1 & 1 & - 1 \\ 1 & 0 & 2 \\ 1 & x^{'} & y^{'} \end{matrix} |

=

\pm

5

\Rightarrow

[(–2x') – (y' – 2) – (x')] =

\pm

10

\Rightarrow

– 3x' – y' + 2 =

\pm

10

\Rightarrow

2 - 4

\lambda

=

\pm

10

\Rightarrow

\lambda

= -2 or

\lambda

= 3

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