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QJEEM20Mac218: JEE Main 2020 Mathematics - Class 11 JEEM20Mac218 Solution: The value of (2. 1 P 0 – 3. 2 P 1 + 4. 3 P 2 .... up to 51 th…
The value of (2.1P0 – 3.2P1 + 4.3P2 .... up to 51th term)
+ (1! – 2! + 3! – ..... up to 51th term) is equal to :
+ (1! – 2! + 3! – ..... up to 51th term) is equal to :
Multiple Choice Options
- A 1
- B 1 + (51)!
- C 1 – 51(51)!
- D 1 + (52)!
Step-by-Step Verified Solution
(2.1P0 – 3.2P1 + 4.3P2 .... up to 51th term)
+ (1! – 2! + 3! – ..... up to 51th term)
= ( 2.1! - 3.2! + 4.3! - ....+ 52.51!)
+ ( 1! – 2! + 3! – ..... + (51)! )
= (2! - 3! + 4! .....+ 52! )
+ ( 1! - 2! + 3! - 4! + .....+ 51! )
= 1 + (52)!
+ (1! – 2! + 3! – ..... up to 51th term)
= ( 2.1! - 3.2! + 4.3! - ....+ 52.51!)
+ ( 1! – 2! + 3! – ..... + (51)! )
= (2! - 3! + 4! .....+ 52! )
+ ( 1! - 2! + 3! - 4! + .....+ 51! )
= 1 + (52)!