Verified Solution • 2025–26 Session moderate

QJEEM20Mab493: JEE Main 2020 Mathematics - Class 11 JEEM20Mab493 Solution: If the number of integral terms in the expansion of (3 1/2 + 5…

If the number of integral terms in the expansion
of (31/2 + 51/8)n is exactly 33, then the least value of n is :

Multiple Choice Options

  • A 264
  • B 256
  • C 128
  • D 248

Step-by-Step Verified Solution

General term of the expression,

Tr+1=nCr(312)n−r(518)r{T_{r + 1}} = {}^n{C_r}{\left( {{3^{{1 \over 2}}}} \right)^{n - r}}{\left( {{5^{{1 \over 8}}}} \right)^r}

=nCr(3)n−r2(5)r8= {}^n{C_r}{\left( 3 \right)^{{{n - r} \over 2}}}{\left( 5 \right)^{{r \over 8}}}

We will get integral term when n−r2{{n - r} \over 2} and r8{r \over 8} are integer

∴\therefore (1) n −- r is multiple of 2

⇒\Rightarrow n −- r = 0, 2, 4, ......

(2) r is multiple of 8

⇒\Rightarrow r = 0, 8, 16, .......

From this two conditions common values are = 0, 8, 16, ....... which will becomes integral terms.

Given that there are 33 integral terms.

Here first integral term at 0th position.

Second integral term at 8th position.

∴\therefore 33th integral term will be at = 0 + (33 −- 1)8 = 256

So, there should be at least 256 terms.

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