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QJEEM20Ma9d85: JEE Main 2020 Mathematics - Class 11 JEEM20Ma9d85 Solution: If the 10 th term of an A.P. is and its 20 th term is , then…

If the 10th term of an A.P. is 120{1 \over {20}} and its 20th term is 110{1 \over {10}} , then the sum of its first 200 terms is

Multiple Choice Options

  • A 100
  • B 10012100{1 \over 2}
  • C 501450{1 \over 4}
  • D 50

Step-by-Step Verified Solution

T10 = a + 9d = 120{1 \over {20}} ....(1)

T20 = a + 19d = 110{1 \over {10}} .....(2)

Equation (2) – (1)

10d = 110{1 \over {10}} - 120{1 \over {20}}

⇒\Rightarrow d = 1200{1 \over {200}}

a + 9200{9 \over {200}} = 120{1 \over {20}}

⇒\Rightarrow a = 1200{1 \over {200}}

S200 = 2002[2200+(200−1)×1200]{{200} \over 2}\left[ {{2 \over {200}} + \left( {200 - 1} \right) \times {1 \over {200}}} \right]

= 100[2200+199200]100\left[ {{2 \over {200}} + {{199} \over {200}}} \right]

= 2012{{201} \over 2} = 10012100{1 \over 2}

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