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QJEEM20Ma8786: JEE Main 2020 Mathematics - Class 11 JEEM20Ma8786 Solution: If the variance of the following frequency distribution :…

If the variance of the following frequency distribution :

Class         : 10–20 20–30 30–40

Frequency :    2          x          2

is 50, then x is equal to____

Step-by-Step Verified Solution

xi = midpoint of class interval
JEE Main 2020 (Online) 4th September Evening Slot Mathematics - Statistics Question 79 English Explanation

Variance( σ2)\sigma^{2}) =∑fi(xi−xˉ)2∑fi=\frac{\sum f_{i}\left( x_{i}-\bar{x} \right)^{2} }{\sum f_{i}}

Also, xˉ=∑fixi∑fi\bar{x} =\frac{\sum f_{i}x_{i}}{\sum f_{i}}

= 30+25x+702+2+x\frac{30+25x+70}{2+2+x} = 25

Given, Variance = 50

∴\therefore 50 = 200+0+2002+2+x\frac{200+0+200}{2+2+x}

⇒\Rightarrow x = 4

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