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QJEEM20Ma71ef: JEE Main 2020 Mathematics - Class 11 JEEM20Ma71ef Solution: If ( 1 + i 1 − i ) m 2 = ( 1 + i 1 − i ) n 3 = 1 , (m, n ∈ N)…

If (1+i1−i)m2=(1+i1−i)n3=1, (m, n ∈ N) then the greatest common divisor of the least values of m and n is _______ .

Step-by-Step Verified Solution

(1+i1−i)m/2=(1+i1−i)n/3=1

⇒((1+i)22)m/2=((1+i)2−2)n/3=1

⇒(i)m/2=(−i)n/3=1 = i4 [ As i4 = 1]

⇒m2=4k1andn3=4k2

⇒ m = 8 k1 and n = 12 k2

Least value of m = 8 and n = 12.

∴ GCD (8, 12) = 4

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