QJEEM20Ma68a0: JEE Main 2020 Mathematics - Class 11 JEEM20Ma68a0 Solution: The least positive value of 'a' for which the equation 2x 2 +…

For real roots Discriminate $$\ge$$ 0.

(a – 10)² – 4$$\left(\frac{33}{2}-2a\right).2$$ $$\ge$$ 0

$$\Rightarrow$$ a² + 100 – 20a – 132 + 16a $$\ge$$ 0

$$\Rightarrow$$ a ² – 4a – 32 $$\ge$$ 0

$$\Rightarrow$$ (a – 8) (a + 4) $$\ge$$ 0

$$\Rightarrow$$ a $$\le$$ -4 $$\cup$$ a $$\ge$$ 8

$$\therefore$$ least positive a = 8