Verified Solution • 2025–26 Session moderate

QJEEM20Ma51b7: JEE Main 2020 Mathematics - Class 12 JEEM20Ma51b7 Solution: lim x → 0 ⁡ ∫ 0 x t sin ⁡ ( 10 t ) d t x is equal to

limx→0⁡∫0xtsin⁡(10t)dtx is equal to

Multiple Choice Options

  • A −15
  • B −110
  • C 0
  • D 110

Step-by-Step Verified Solution

limx→0⁡∫0xtsin⁡(10t)dtx

This is in 00 form.

So apply newton leibniz rule

limx→0⁡x.sin⁡(10x)−01 = 0

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