Verified Solution • 2025–26 Session
moderate
QJEEM20Ma5172: JEE Main 2020 Mathematics - Class 11 JEEM20Ma5172 Solution: Two families with three members each and one family with four…
Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?
Multiple Choice Options
- A 2! 3! 4!
- B (3!)3.(4!)
- C 3! (4!)3
- D (3!)2.(4!)
Step-by-Step Verified Solution
F1 3 members
F2 3 members
F3 4 members
Total arrangements of three families = 3!
Arrangement between members of F1 family = 3!
Arrangement between members of F2 family = 3!
Arrangement between members of F3 family = 4!
Total numbers of ways can they be seated so that the same family members are not separated
= 3! 3! 3! 4!
= (3!)3.(4!)
F2 3 members
F3 4 members
Total arrangements of three families = 3!
Arrangement between members of F1 family = 3!
Arrangement between members of F2 family = 3!
Arrangement between members of F3 family = 4!
Total numbers of ways can they be seated so that the same family members are not separated
= 3! 3! 3! 4!
= (3!)3.(4!)