QJEEM20Ma4f5e: JEE Main 2020 Mathematics - Class 12 JEEM20Ma4f5e Solution: A random variable X has the following probability distribution…

Question

Verified Solution • 2025–26 Session moderate

A random variable X has the following probability distribution :

X:	1	2	3	4	5
P(X):	K²	2K	K	2K	5K²

Then P(X > 2) is equal to :

Accepted Answer

\sum_{i = 1}^{5} P (X)

= 1

\Rightarrow

K² + 2K + K + 2K + 5K² = 1

\Rightarrow

6K² + 5K – 1 = 0

\Rightarrow

(6K - 1)(k + 1) = 0

\Rightarrow

K =

\frac{1}{6}

and K = -1(rejected)

∴

P(X

>

2)

= K + 2K + 5K²

=

\frac{1}{6} + \frac{2}{6} + \frac{5}{36}

=

\frac{23}{36}

Step-by-Step Verified Solution